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Find the
y-coordinate of the
y-intercept of the polynomial function defined below.

f(x)=7x^(2)-6x+2x^(4)+3x^(3)
Answer:

Find the $y$ -coordinate of the $y$ -intercept of the polynomial function defined below. $\newline$ $f(x)=7 x^{2}-6 x+2 x^{4}+3 x^{3}$ $\newline$ Answer:

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Find derivatives of sine and cosine functions

Full solution

Q. Find the

y

-coordinate of the

y

-intercept of the polynomial function defined below.

\newline

f(x)=7 x^{2}-6 x+2 x^{4}+3 x^{3}

\newline

Answer:

Define y-intercept: To find the y-coordinate of the y-intercept of the function $f(x)$ , we need to evaluate $f(x)$ at $x = 0$ , because the y-intercept occurs where the graph of the function crosses the y-axis, which is at $x = 0$ .
Substitute $x=0$ : Substitute $x = 0$ into the polynomial function $f(x) = 7x^2 - 6x + 2x^4 + 3x^3$ . $\newline$ $f(0) = 7(0)^2 - 6(0) + 2(0)^4 + 3(0)^3$
Simplify expression: Simplify the expression by calculating the value of each term with $x = 0$ . $\newline$ $f(0) = 7(0) - 6(0) + 2(0) + 3(0)$ $\newline$ $f(0) = 0 - 0 + 0 + 0$ $\newline$ $f(0) = 0$
Find y-coordinate: The y-coordinate of the y-intercept is the value of $f(0)$ , which we have found to be $0$ .

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