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Find the
y-coordinate of the
y-intercept of the polynomial function defined below.

f(x)=-2x(x^(2)-1)(4x-1)(4x+4)
Answer:

Find the $y$ -coordinate of the $y$ -intercept of the polynomial function defined below. $\newline$ $f(x)=-2 x\left(x^{2}-1\right)(4 x-1)(4 x+4)$ $\newline$ Answer:

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Find derivatives of sine and cosine functions

Full solution

Q. Find the

y

-coordinate of the

y

-intercept of the polynomial function defined below.

\newline

f(x)=-2 x\left(x^{2}-1\right)(4 x-1)(4 x+4)

\newline

Answer:

Evaluate at $x = 0$ : To find the $y$ -coordinate of the $y$ -intercept of the function $f(x)$ , we need to evaluate $f(x)$ at $x = 0$ , because the $y$ -intercept occurs where the graph of the function crosses the $y$ -axis, and the $x$ -coordinate of any point on the $y$ -axis is $y$ $0$ .
Substitute $x = 0$ : Substitute $x = 0$ into the function $f(x) = -2x(x^2 - 1)(4x - 1)(4x + 4)$ . $\newline$ $f(0) = -2\cdot 0\cdot (0^2 - 1)(4\cdot 0 - 1)(4\cdot 0 + 4)$
Simplify the expression: Simplify the expression by performing the multiplication. $\newline$ $f(0) = -2 \times 0 \times (0 - 1)(0 - 1)(0 + 4)$ $\newline$ $f(0) = -2 \times 0 \times (-1)(-1)(4)$ $\newline$ $f(0) = -2 \times 0 \times 1 \times 4$ $\newline$ $f(0) = 0$

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