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Find the volume of a right circular cone that has a height of 
5.2cm and a base with a radius of 
19cm. Round your answer to the nearest tenth of a cubic centimeter.
Answer: 
cm^(3)

Find the volume of a right circular cone that has a height of 5.2 cm 5.2 \mathrm{~cm} and a base with a radius of 19 cm 19 \mathrm{~cm} . Round your answer to the nearest tenth of a cubic centimeter.\newlineAnswer: cm3 \mathrm{cm}^{3}

Full solution

Q. Find the volume of a right circular cone that has a height of 5.2 cm 5.2 \mathrm{~cm} and a base with a radius of 19 cm 19 \mathrm{~cm} . Round your answer to the nearest tenth of a cubic centimeter.\newlineAnswer: cm3 \mathrm{cm}^{3}
  1. Identify formula: Identify the formula for the volume of a right circular cone. The formula for the volume VV of a right circular cone is V=13πr2hV = \frac{1}{3}\pi r^2 h, where rr is the radius of the base and hh is the height of the cone.
  2. Plug values: Plug the given values into the formula.\newlineUsing the given radius r=19 cmr = 19 \text{ cm} and height h=5.2 cmh = 5.2 \text{ cm}, we substitute these values into the formula to get V=13π(19 cm)2(5.2 cm)V = \frac{1}{3}\pi(19 \text{ cm})^2(5.2 \text{ cm}).
  3. Calculate base area: Calculate the base area and multiply by the height.\newlineFirst, we calculate the area of the base, which is πr2=π(19 cm)2=π(361 cm2)\pi r^2 = \pi(19 \text{ cm})^2 = \pi(361 \text{ cm}^2). Then we multiply this by the height and divide by 33 to get the volume: V=13π(361 cm2)(5.2 cm)V = \frac{1}{3}\pi(361 \text{ cm}^2)(5.2 \text{ cm}).
  4. Perform multiplication: Perform the multiplication and division to find the volume.\newlineNow we calculate V=(13)π(361 cm2)(5.2 cm)=(13)(3.14159)(361 cm2)(5.2 cm)(13)(3.14159)(1877.2 cm3)1963.4952 cm3V = (\frac{1}{3})\pi(361 \text{ cm}^2)(5.2 \text{ cm}) = (\frac{1}{3})(3.14159)(361 \text{ cm}^2)(5.2 \text{ cm}) \approx (\frac{1}{3})(3.14159)(1877.2 \text{ cm}^3) \approx 1963.4952 \text{ cm}^3.
  5. Round result: Round the result to the nearest tenth of a cubic centimeter.\newlineRounding 1963.4952cm31963.4952\,\text{cm}^3 to the nearest tenth gives us approximately 1963.5cm31963.5\,\text{cm}^3.

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