Find the volume of a pyramid with a square base, where the perimeter of the base is 15.3cm and the height of the pyramid is 9.5cm. Round your answer to the nearest tenth of a cubic centimeter. Answer: cm^(3)

Determine Side Length: To find the volume of a pyramid with a square base, we first need to determine the length of one side of the square base. Since the perimeter of the base is the sum of all four sides, we divide the perimeter by 4. Perimeter of the base = 15.3 cm Length of one side of the square base = Perimeter ÷ 4 Length of one side = 15.3 cm ÷ 4Calculate Base Area: Now, let's calculate the length of one side of the square base. Length of one side = 15.3 cm ÷ 4 = 3.825 cmFind Pyramid Volume: Next, we calculate the area of the square base by squaring the length of one side. Area of the base = (Length of one side)² Area of the base = (3.825 cm)²Calculate Final Volume: Let's perform the calculation for the area of the base. Area of the base = (3.825 cm)² = 14.630625 cm²Round to Nearest Tenth: Now we can find the volume of the pyramid using the formula for the volume of a pyramid with a square base: Volume = (1/3) * (Base Area) * (Height). Volume = (1/3) * (14.630625 cm²) * (9.5 cm)Let's calculate the volume of the pyramid. Volume = (1/3) * (14.630625 cm²) * (9.5 cm) ≈ 46.29796875 cm³Finally, we round the volume to the nearest tenth of a cubic centimeter. Volume ≈ 46.3 cm³

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Find the volume of a pyramid with a square base, where the perimeter of the base is
15.3cm and the height of the pyramid is
9.5cm. Round your answer to the nearest tenth of a cubic centimeter.
Answer:
cm^(3)

Find the volume of a pyramid with a square base, where the perimeter of the base is $15.3 \mathrm{~cm}$ and the height of the pyramid is $9.5 \mathrm{~cm}$ . Round your answer to the nearest tenth of a cubic centimeter. $\newline$ Answer: $\mathrm{cm}^{3}$

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Q. Find the volume of a pyramid with a square base, where the perimeter of the base is

15.3 \mathrm{~cm}

and the height of the pyramid is

9.5 \mathrm{~cm}

. Round your answer to the nearest tenth of a cubic centimeter.

\newline

Answer:

\mathrm{cm}^{3}

Determine Side Length: To find the volume of a pyramid with a square base, we first need to determine the length of one side of the square base. Since the perimeter of the base is the sum of all four sides, we divide the perimeter by $4$ . $\newline$ Perimeter of the base $= 15.3\,\text{cm}$ $\newline$ Length of one side of the square base $= \text{Perimeter} \div 4$ $\newline$ Length of one side $= 15.3\,\text{cm} \div 4$
Calculate Base Area: Now, let's calculate the length of one side of the square base. $\newline$ Length of one side = $15.3 \, \text{cm} \div 4 = 3.825 \, \text{cm}$
Find Pyramid Volume: Next, we calculate the area of the square base by squaring the length of one side. $\newline$ Area of the base = (Length of one side) $\newline$ Area of the base = $(3.825 \, \text{cm})^2$
Calculate Final Volume: Let's perform the calculation for the area of the base. $\newline$ Area of the base = $(3.825 \, \text{cm})^2 = 14.630625 \, \text{cm}^2$
Round to Nearest Tenth: Now we can find the volume of the pyramid using the formula for the volume of a pyramid with a square base: Volume $= \frac{1}{3} \times (\text{Base Area}) \times (\text{Height})$ . $\newline$ Volume $= \frac{1}{3} \times (14.630625 \, \text{cm}^2) \times (9.5 \, \text{cm})$
Round to Nearest Tenth: Now we can find the volume of the pyramid using the formula for the volume of a pyramid with a square base: Volume = $(\frac{1}{3}) \times (\text{Base Area}) \times (\text{Height})$ . $\text{Volume} = (\frac{1}{3}) \times (14.630625 \, \text{cm}^2) \times (9.5 \, \text{cm})$ Let's calculate the volume of the pyramid. $\text{Volume} = (\frac{1}{3}) \times (14.630625 \, \text{cm}^2) \times (9.5 \, \text{cm}) \approx 46.29796875 \, \text{cm}^3$
Round to Nearest Tenth: Now we can find the volume of the pyramid using the formula for the volume of a pyramid with a square base: Volume = $(\frac{1}{3}) \times (\text{Base Area}) \times (\text{Height})$ . $\text{Volume} = (\frac{1}{3}) \times (14.630625 \text{ cm}^2) \times (9.5 \text{ cm})$ Let's calculate the volume of the pyramid. $\text{Volume} = (\frac{1}{3}) \times (14.630625 \text{ cm}^2) \times (9.5 \text{ cm}) \approx 46.29796875 \text{ cm}^3$ Finally, we round the volume to the nearest tenth of a cubic centimeter. $\text{Volume} \approx 46.3 \text{ cm}^3$