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Let’s check out your problem:
Find the value:
3
×
7
r
+
5
×
8
s
r
=
14
s
=
8
3 \times 7r + 5 \times 8s \quad r=14 \quad s=8
3
×
7
r
+
5
×
8
s
r
=
14
s
=
8
View step-by-step help
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Math Problems
Algebra 1
Solve linear equations with variables on both sides
Full solution
Q.
Find the value:
3
×
7
r
+
5
×
8
s
r
=
14
s
=
8
3 \times 7r + 5 \times 8s \quad r=14 \quad s=8
3
×
7
r
+
5
×
8
s
r
=
14
s
=
8
Plug in values:
First, plug in the values of
r
r
r
and
s
s
s
into the expression:
3
(
7
r
)
+
5
(
8
s
)
3(7r) + 5(8s)
3
(
7
r
)
+
5
(
8
s
)
.
Calculate
7
r
7r
7
r
and
8
s
8s
8
s
:
Now calculate the value of
7
r
7r
7
r
and
8
s
8s
8
s
:
7
(
14
)
7(14)
7
(
14
)
and
8
(
8
)
8(8)
8
(
8
)
.
Multiply by coefficients:
7
7
7
times
14
14
14
is
98
98
98
, and
8
8
8
times
8
8
8
is
64
64
64
.
Calculate final value:
Next, multiply these by their coefficients:
3
(
98
)
+
5
(
64
)
3(98) + 5(64)
3
(
98
)
+
5
(
64
)
.
Add values together:
3
×
98
3 \times 98
3
×
98
is
294
294
294
, and
5
×
64
5 \times 64
5
×
64
is
320
320
320
.
Get final sum:
Finally, add
294
294
294
and
320
320
320
together to get the final value.
Get final sum:
Finally, add
294
294
294
and
320
320
320
together to get the final value.The sum of
294
294
294
and
320
320
320
is
614
614
614
.
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