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Find the sum of the first 10 terms of the following series, to the nearest integer.

6,36,216,dots
Answer:

Find the sum of the first 1010 terms of the following series, to the nearest integer.\newline6,36,216, 6,36,216, \ldots \newlineAnswer:

Full solution

Q. Find the sum of the first 1010 terms of the following series, to the nearest integer.\newline6,36,216, 6,36,216, \ldots \newlineAnswer:
  1. Recognize Pattern: Recognize the pattern in the series.\newlineThe series 66, 3636, 216216, ... appears to be a geometric series where each term is multiplied by 66 to get the next term. This means the common ratio (rr) is 66.
  2. Identify Formula: Identify the formula for the sum of the first nn terms of a geometric series.\newlineThe formula for the sum of the first nn terms of a geometric series is Sn=a(1rn)(1r)S_n = \frac{a(1 - r^n)}{(1 - r)}, where SnS_n is the sum of the first nn terms, aa is the first term, rr is the common ratio, and nn is the number of terms.
  3. Plug in Values: Plug in the values into the formula.\newlineHere, a=6a = 6, r=6r = 6, and n=10n = 10. So, we have S10=6(1610)/(16)S_{10} = 6(1 - 6^{10}) / (1 - 6).
  4. Calculate Sum: Calculate the sum using the formula.\newlineS10=6(1610)/(16)S_{10} = 6(1 - 6^{10}) / (1 - 6)\newlineS10=6(160466176)/(5)S_{10} = 6(1 - 60466176) / (-5)\newlineS10=6(60466175)/(5)S_{10} = 6(-60466175) / (-5)\newlineS10=362797050/(5)S_{10} = -362797050 / (-5)\newlineS10=72559410S_{10} = 72559410
  5. Round to Integer: Round the sum to the nearest integer.\newlineThe sum to the nearest integer is 7255941072559410, which is already an integer, so no rounding is necessary.

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