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Find the missing number so that the equation has infinitely many solutions.\newline4x+15=4x+-4x + 15 = -4x + \underline{\hspace{1cm}}

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Q. Find the missing number so that the equation has infinitely many solutions.\newline4x+15=4x+-4x + 15 = -4x + \underline{\hspace{1cm}}
  1. Identify Identical Coefficients: To determine the missing number for the equation to have infinitely many solutions, we need to make the left-hand side (LHS) and the right-hand side (RHS) of the equation identical. This means that the coefficients of xx must be the same on both sides, and the constant terms must also be the same.
  2. Check Constant Terms: Looking at the equation -4x + 15 = -4x + ____, we can see that the coefficients of xx are already the same on both sides (4-4 on the LHS and 4-4 on the RHS). Therefore, we do not need to change the coefficients.
  3. Fill in Missing Number: Now we need to make sure that the constant terms on both sides of the equation are the same. The constant term on the LHS is 1515. For the equation to have infinitely many solutions, the constant term on the RHS must also be 1515.
  4. Fill in Missing Number: Now we need to make sure that the constant terms on both sides of the equation are the same. The constant term on the LHS is 1515. For the equation to have infinitely many solutions, the constant term on the RHS must also be 1515.We can now fill in the missing number in the equation. The equation with the missing number filled in is 4x+15=4x+15-4x + 15 = -4x + 15.

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