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Find the limit as 
x approaches negative infinity.

lim_(x rarr-oo)(x^(5)+4x^(2))/(sqrt(x^(10)+8x^(7)))=

Find the limit as x x approaches negative infinity.\newlinelimxx5+4x2x10+8x7= \lim _{x \rightarrow-\infty} \frac{x^{5}+4 x^{2}}{\sqrt{x^{10}+8 x^{7}}}=

Full solution

Q. Find the limit as x x approaches negative infinity.\newlinelimxx5+4x2x10+8x7= \lim _{x \rightarrow-\infty} \frac{x^{5}+4 x^{2}}{\sqrt{x^{10}+8 x^{7}}}=
  1. Analyze Function and Limit: Analyze the given function and the limit to be found.\newlineWe need to find the limit of the function (x5+4x2)/(x10+8x7)(x^5 + 4x^2) / (\sqrt{x^{10} + 8x^7}) as xx approaches negative infinity. To do this, we will look for the dominant terms in the numerator and the denominator.
  2. Identify Dominant Terms: Identify the dominant terms in the numerator and the denominator.\newlineIn the numerator, the dominant term is x5x^5 because it has the highest power of xx. In the denominator, the dominant term inside the square root is x10x^{10}, which is the highest power of xx there.
  3. Simplify by Dividing: Simplify the function by dividing the numerator and the denominator by x5x^5. We divide each term in the numerator and the square root of each term in the denominator by x5x^5 to simplify the expression. This gives us:\newlinelimxx5/x5+4x2/x5x10/x5+8x7/x5\lim_{x \rightarrow -\infty} \frac{x^5/x^5 + 4x^2/x^5}{\sqrt{x^{10}/x^5 + 8x^7/x^5}}\newlineSimplifying further, we get:\newlinelimx1+4/x3x5+8x2\lim_{x \rightarrow -\infty} \frac{1 + 4/x^3}{\sqrt{x^5 + 8x^2}}
  4. Evaluate Limit: Evaluate the limit of the simplified function as xx approaches negative infinity.\newlineAs xx approaches negative infinity, the terms 4x3\frac{4}{x^3} and 8x2x5\frac{8x^2}{x^5} in the simplified function will approach 00 because they have xx in the denominator with a positive power. This leaves us with:\newlinelimx1x5\lim_{x \to -\infty} \frac{1}{\sqrt{x^5}}\newlineSince xx is approaching negative infinity, we need to consider the behavior of x5\sqrt{x^5}. The square root function is not defined for negative numbers, but since we are dealing with x5x^5, which is an odd power, the result will be negative and the square root of a negative number is not a real number. This indicates that we have made a mistake in our simplification process because we cannot take the square root of a negative number.