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Find the limit as 
x approaches negative infinity.

lim_(x rarr-oo)(sqrt(9x^(2)+2))/(2x-9)=

Find the limit as x x approaches negative infinity.\newlinelimx9x2+22x9= \lim _{x \rightarrow-\infty} \frac{\sqrt{9 x^{2}+2}}{2 x-9}=

Full solution

Q. Find the limit as x x approaches negative infinity.\newlinelimx9x2+22x9= \lim _{x \rightarrow-\infty} \frac{\sqrt{9 x^{2}+2}}{2 x-9}=
  1. Identify highest power of x: Identify the highest power of x in the numerator and denominator.\newlineIn the expression (9x2+2)/(2x9)(\sqrt{9x^{2}+2})/(2x-9), the highest power of x in the numerator inside the square root is x2x^2, and in the denominator, it is xx.
  2. Divide by highest power: Divide the numerator and the denominator by the highest power of xx in the denominator.\newlineTo simplify the limit, we divide both the numerator and the denominator by xx. This gives us 9+2x229x\frac{\sqrt{9 + \frac{2}{x^2}}}{2 - \frac{9}{x}}.
  3. Take limit as xx approaches: Take the limit as xx approaches negative infinity.\newlineAs xx approaches negative infinity, the terms 2x2\frac{2}{x^2} and 9x\frac{9}{x} in the expression 9+2x229x\frac{\sqrt{9 + \frac{2}{x^2}}}{2 - \frac{9}{x}} will approach 00. This simplifies the expression to 9+020\frac{\sqrt{9 + 0}}{2 - 0} which is 92\frac{\sqrt{9}}{2}.
  4. Calculate simplified limit: Calculate the simplified limit. The simplified limit is 9/2\sqrt{9}/2, which is 3/23/2.