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Find the limit as 
x approaches negative infinity.

lim_(x rarr-oo)(5x^(3)-3x)/(sqrt(4x^(6)-7))=

Find the limit as x x approaches negative infinity.\newlinelimx5x33x4x67= \lim _{x \rightarrow-\infty} \frac{5 x^{3}-3 x}{\sqrt{4 x^{6}-7}}=

Full solution

Q. Find the limit as x x approaches negative infinity.\newlinelimx5x33x4x67= \lim _{x \rightarrow-\infty} \frac{5 x^{3}-3 x}{\sqrt{4 x^{6}-7}}=
  1. Identify highest power of x: Identify the highest power of xx in both the numerator and the denominator.\newlineIn the numerator, the highest power of xx is x3x^3. In the denominator, the highest power of xx inside the square root is x6x^6, which becomes x3x^3 when taken outside the square root.
  2. Divide by highest power: Divide both the numerator and the denominator by x3x^3, the highest power of xx found in the previous step.\newlinelimx5x3x33xx34x6x37x3\lim_{x \rightarrow -\infty} \frac{\frac{5x^3}{x^3} - \frac{3x}{x^3}}{\sqrt{\frac{4x^6}{x^3} - \frac{7}{x^3}}}
  3. Simplify expression: Simplify the expression by canceling out the x3x^3 terms and reducing the fractions.limx53x247x6\lim_{x \to -\infty} \frac{5 - \frac{3}{x^2}}{\sqrt{4 - \frac{7}{x^6}}}
  4. Approach negative infinity: As xx approaches negative infinity, the terms with xx in the denominator approach zero.limx(50)(40)\lim_{x \rightarrow -\infty} \frac{(5 - 0)}{(\sqrt{4 - 0})}
  5. Evaluate limit: Evaluate the limit by substituting the values that approach zero.\newlinelimx54=52\lim_{x \rightarrow -\infty} \frac{5}{\sqrt{4}} = \frac{5}{2}