Find the inverse function of the function f(x)=2x-5. f^(-1)(x)=(x-2)/(5) f^(-1)(x)=(x+2)/(5) f^(-1)(x)=(x-5)/(2) f^(-1)(x)=(x+5)/(2)

Replace with y: To find the inverse function, we first replace f(x) with y: y = 2x - 5Swap x and y: Next, we swap x and y to solve for the new y, which will give us the inverse function: x = 2y - 5Solve for new y: Now, we solve for y by adding 5 to both sides of the equation: x + 5 = 2yIsolate y: Finally, we divide both sides by 2 to isolate y: y = (x + 5) / 2 This is the inverse function of f(x).

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Find the inverse function of the function
f(x)=2x-5.

f^(-1)(x)=(x-2)/(5)

f^(-1)(x)=(x+2)/(5)

f^(-1)(x)=(x-5)/(2)

f^(-1)(x)=(x+5)/(2)

Find the inverse function of the function $f(x)=2 x-5$ . $\newline$ $f^{-1}(x)=\frac{x-2}{5}$ $\newline$ $f^{-1}(x)=\frac{x+2}{5}$ $\newline$ $f^{-1}(x)=\frac{x-5}{2}$ $\newline$ $f^{-1}(x)=\frac{x+5}{2}$

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Q. Find the inverse function of the function

f(x)=2 x-5

\newline

f^{-1}(x)=\frac{x-2}{5}

\newline

f^{-1}(x)=\frac{x+2}{5}

\newline

f^{-1}(x)=\frac{x-5}{2}

\newline

f^{-1}(x)=\frac{x+5}{2}

Replace with $y$ : To find the inverse function, we first replace $f(x)$ with $y$ : $y = 2x - 5$
Swap x and y: Next, we swap x and y to solve for the new y, which will give us the inverse function: $\newline$ $x = 2y - 5$
Solve for new y: Now, we solve for $y$ by adding $5$ to both sides of the equation: $\newline$ $x + 5 = 2y$
Isolate $y$ : Finally, we divide both sides by $2$ to isolate $y$ : $y = \frac{x + 5}{2}$ This is the inverse function of $f(x)$ .