Find the equation of the normal to the curve {:[(dy)/(dx)=1.84e^(0.5 x)" at "x=1],

Find Tangent Slope: First, we need to find the slope of the tangent to the curve at x=1.Calculate Tangent Slope: Now, we calculate the actual value of the slope at x=1.Calculate Normal Slope: The slope of the normal is the negative reciprocal of the slope of the tangent.Find Curve's y-coordinate: Now we find the y-coordinate of the curve at x=1.

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Find the equation of the normal to the curve. $\newline$ $\frac{dy}{dx}=1.84e^{0.5 x} \text{ at } x=1$

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Q. Find the equation of the normal to the curve.

\newline

\frac{dy}{dx}=1.84e^{0.5 x} \text{ at } x=1

Find Tangent Slope: First, we need to find the slope of the tangent to the curve at $x=1$ .
Calculate Tangent Slope: Now, we calculate the actual value of the slope at $x=1$ .
Calculate Normal Slope: The slope of the normal is the negative reciprocal of the slope of the tangent, i.e., if the slope of the tangent is $m$ , then the slope of the normal is $-\frac{1}{m}$ .
Find Curve's y-coordinate: Now we find the y-coordinate of the curve at $x=1$ .