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Find the equation of the axis of symmetry of the following parabola using graphing technology. y=x^(2)-2x+8 Answer:

Find the equation of the axis of symmetry of the following parabola using graphing technology.\newliney=x2−2x+8 y=x^{2}-2 x+8 \newlineAnswer:

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Q. Find the equation of the axis of symmetry of the following parabola using graphing technology.\newliney=x2−2x+8 y=x^{2}-2 x+8 \newlineAnswer:
  1. Find Axis of Symmetry Formula: The equation of a parabola in the form y=ax2+bx+cy = ax^2 + bx + c has an axis of symmetry that can be found using the formula x=−b2ax = -\frac{b}{2a}.
  2. Identify Coefficients: For the given parabola y=x2−2x+8y = x^2 - 2x + 8, the coefficients are a=1a = 1 and b=−2b = -2.
  3. Substitute into Formula: Substitute the values of aa and bb into the formula to find the axis of symmetry: x=−(−2)/(2⋅1)x = -(-2)/(2\cdot1).
  4. Calculate Value: Calculate the value: x=2(2∗1)=22=1x = \frac{2}{(2*1)} = \frac{2}{2} = 1.
  5. Final Axis of Symmetry: The equation of the axis of symmetry is therefore x=1x = 1.

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