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Find the equation of the axis of symmetry of the following parabola using graphing technology. y=-2x^(2)-20 x-60 Answer:

Find the equation of the axis of symmetry of the following parabola using graphing technology.\newliney=−2x2−20x−60 y=-2 x^{2}-20 x-60 \newlineAnswer:

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Q. Find the equation of the axis of symmetry of the following parabola using graphing technology.\newliney=−2x2−20x−60 y=-2 x^{2}-20 x-60 \newlineAnswer:
  1. Identify coefficients: The equation of a parabola in the form y=ax2+bx+cy = ax^2 + bx + c has an axis of symmetry that can be found using the formula x=−b2ax = -\frac{b}{2a}. In this case, the parabola is y=−2x2−20x−60y = -2x^2 - 20x - 60. We identify a=−2a = -2 and b=−20b = -20.
  2. Substitute into formula: We substitute the values of aa and bb into the formula for the axis of symmetry.x=−(−20)/(2⋅−2)x = -(-20)/(2 \cdot -2)x=20/(−4)x = 20/(-4)x=−5x = -5
  3. Equation of axis: The equation of the axis of symmetry is a vertical line passing through the xx-coordinate we found.\newlineTherefore, the equation of the axis of symmetry is x=−5x = -5.

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