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Find the equation of the axis of symmetry of the following parabola algebraically.

y=2x^(2)+24 x+70
Answer:

Find the equation of the axis of symmetry of the following parabola algebraically.\newliney=2x2+24x+70 y=2 x^{2}+24 x+70 \newlineAnswer:

Full solution

Q. Find the equation of the axis of symmetry of the following parabola algebraically.\newliney=2x2+24x+70 y=2 x^{2}+24 x+70 \newlineAnswer:
  1. Identify General Form: Identify the general form of the quadratic equation.\newlineThe given parabola is in the form y=ax2+bx+cy = ax^2 + bx + c, where aa, bb, and cc are constants.\newlineFor the given equation y=2x2+24x+70y = 2x^2 + 24x + 70, we have:\newlinea=2a = 2, b=24b = 24, and c=70c = 70.
  2. Use Axis of Symmetry Formula: Use the formula for the axis of symmetry for a parabola.\newlineThe axis of symmetry for a parabola given by y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}.
  3. Substitute Values: Substitute the values of aa and bb into the formula.\newlineSubstitute a=2a = 2 and b=24b = 24 into the formula x=b2ax = -\frac{b}{2a} to find the axis of symmetry.\newlinex=242×2x = -\frac{24}{2 \times 2}\newlinex=244x = -\frac{24}{4}\newlinex=6x = -6
  4. Write Equation: Write the equation of the axis of symmetry.\newlineThe equation of the axis of symmetry is a vertical line passing through the xx-coordinate found in Step 33.\newlineTherefore, the equation of the axis of symmetry is x=6x = -6.

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