Find the derivative of the function f(x)=ln(x^(2)-3x+2).

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Find the derivative of the function  f(x)=ln(x^(2)-3x+2).

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Identify Functions: To find the derivative of the function f(x) = ln(x^2 - 3x + 2), we will use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.Find Outer and Inner: First, let's identify the outer function and the inner function. The outer function is g(u) = ln(u), and the inner function is u(x) = x^2 - 3x + 2.Derivative of Outer: The derivative of the outer function g(u) = ln(u) with respect to u is 1/u. We will apply this after we find the derivative of the inner function.Derivative of Inner: Now, let's find the derivative of the inner function u(x) = x^2 - 3x + 2. The derivative of x^2 is 2x, the derivative of -3x is -3, and the derivative of a constant like 2 is 0.Combine Inner Derivative: Combining the derivatives of the terms in the inner function, we get u'(x) = 2x - 3.Apply Chain Rule: Now we can apply the chain rule. The derivative of the function f(x) with respect to x is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. f'(x) = g'(u(x)) * u'(x)Substitute Derivatives: Substituting the derivatives we found, we get: f'(x) = (1/(x^2 - 3x + 2)) * (2x - 3)Simplify Expression: Simplifying the expression, we leave it as is because it is the simplest form for the derivative of the given function. f'(x) = (2x - 3) / (x^2 - 3x + 2)

Find the derivative of the function $f(x)=\ln(x^{2}-3x+2)$ .

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Find the derivative of the function f(x)=ln⁡(x2−3x+2)f(x)=\ln(x^{2}-3x+2)f(x)=ln(x2−3x+2).

Find the derivative of the function $f(x)=\ln(x^{2}-3x+2)$ .