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Find the derivative of the following function.

y=ln(5x^(2))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=ln(5x2) y=\ln \left(5 x^{2}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=ln(5x2) y=\ln \left(5 x^{2}\right) \newlineAnswer: y= y^{\prime}=
  1. Identify Function: Identify the function to differentiate.\newlineThe function given is y=ln(5x2)y = \ln(5x^{2}). We need to find the derivative of this function with respect to xx.
  2. Apply Chain Rule: Apply the chain rule for differentiation. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is ln(u)\ln(u) and the inner function is u=5x2u = 5x^{2}.
  3. Differentiate Outer Function: Differentiate the outer function.\newlineThe derivative of ln(u)\ln(u) with respect to uu is 1u\frac{1}{u}. So, if y=ln(u)y = \ln(u), then y=1uy' = \frac{1}{u}.
  4. Differentiate Inner Function: Differentiate the inner function.\newlineThe inner function is u=5x2u = 5x^{2}. The derivative of 5x25x^{2} with respect to xx is 10x10x, because we use the power rule which states that the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}.
  5. Apply Chain Rule: Apply the chain rule.\newlineUsing the chain rule, the derivative of yy with respect to xx is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. This gives us y=(1u)(dudx)y' = (\frac{1}{u}) \cdot (\frac{du}{dx}).
  6. Substitute and Simplify: Substitute uu with 5x25x^{2} and dudx\frac{du}{dx} with 10x10x. Substituting the expressions for uu and dudx\frac{du}{dx} into the chain rule formula, we get y=15x210xy' = \frac{1}{5x^{2}} \cdot 10x.
  7. Simplify Expression: Simplify the expression.\newlineSimplifying the expression for yy', we get y=10x5x2y' = \frac{10x}{5x^{2}}. We can simplify this further by canceling out an xx from the numerator and denominator, which gives us y=105xy' = \frac{10}{5x}.
  8. Simplify Constant: Simplify the constant.\newlineSimplifying the constant 105\frac{10}{5}, we get y=2xy' = \frac{2}{x}.

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