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Find the derivative of the following function.

y=ln(4x^(6))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=ln(4x6) y=\ln \left(4 x^{6}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=ln(4x6) y=\ln \left(4 x^{6}\right) \newlineAnswer: y= y^{\prime}=
  1. Identify function: Identify the function to differentiate.\newlineThe function given is y=ln(4x6)y = \ln(4x^{6}). We need to find the derivative of this function with respect to xx.
  2. Apply chain rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. Here, the outer function is ln(u)\ln(u) and the inner function is u=4x6u = 4x^{6}.
  3. Differentiate outer function: Differentiate the outer function.\newlineThe derivative of ln(u)\ln(u) with respect to uu is 1u\frac{1}{u}. So, if y=ln(u)y = \ln(u), then y=1uy' = \frac{1}{u}.
  4. Differentiate inner function: Differentiate the inner function.\newlineThe inner function is u=4x6u = 4x^{6}. The derivative of uu with respect to xx is u=ddx(4x6)=4×6x61=24x5u' = \frac{d}{dx}(4x^{6}) = 4 \times 6x^{6-1} = 24x^{5}.
  5. Apply chain rule: Apply the chain rule.\newlineUsing the chain rule, the derivative of yy with respect to xx is y=(1/u)(du/dx)y' = (1/u) \cdot (du/dx). Substituting u=4x6u = 4x^{6} and du/dx=24x5du/dx = 24x^{5}, we get y=(1/(4x6))(24x5)y' = (1/(4x^{6})) \cdot (24x^{5}).
  6. Simplify expression: Simplify the expression.\newlineSimplify yy' by multiplying the terms. y=24x54x6=244x56=6x1y' = \frac{24x^{5}}{4x^{6}} = \frac{24}{4}x^{5-6} = 6x^{-1}.
  7. Write final answer: Write the final answer.\newlineThe derivative of y=ln(4x6)y = \ln(4x^{6}) with respect to xx is y=6x1y' = 6x^{-1}, which can also be written as y=6xy' = \frac{6}{x}.

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