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Find the derivative of the following function.

y=e^(2x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=e2x4 y=e^{2 x^{4}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=e2x4 y=e^{2 x^{4}} \newlineAnswer: y= y^{\prime}=
  1. Identify Function: Identify the function and its components.\newlineThe function y=e2x4y = e^{2x^{4}} is an exponential function where the exponent is a function of xx itself, namely 2x42x^{4}.
  2. Apply Chain Rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is eue^u and the inner function is u=2x4u = 2x^{4}.
  3. Differentiate Outer Function: Differentiate the outer function with respect to the inner function uu. The derivative of eue^u with respect to uu is eue^u. So, (d/du)(eu)=eu(d/du)(e^u) = e^u.
  4. Differentiate Inner Function: Differentiate the inner function u=2x4u = 2x^{4} with respect to xx. Using the power rule, the derivative of 2x42x^{4} with respect to xx is 8x38x^{3}. So, (d/dx)(2x4)=8x3(d/dx)(2x^{4}) = 8x^{3}.
  5. Apply Chain Rule: Apply the chain rule using the derivatives from steps 33 and 44.\newlineThe derivative of yy with respect to xx is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. Therefore, y=e2x4×8x3y' = e^{2x^{4}} \times 8x^{3}.
  6. Simplify Derivative: Simplify the expression for the derivative. y=8x3e2x4y' = 8x^{3} \cdot e^{2x^{4}}.

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