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Find the derivative of the following function.

y=7^(9x^(4)+4x^(3))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=79x4+4x3 y=7^{9 x^{4}+4 x^{3}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=79x4+4x3 y=7^{9 x^{4}+4 x^{3}} \newlineAnswer: y= y^{\prime}=
  1. Find Derivative Function: We need to find the derivative of the function y=79x4+4x3y=7^{9x^{4}+4x^{3}}. To do this, we will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  2. Define Inner Function: Let's denote the inner function as u=9x4+4x3u=9x^{4}+4x^{3}. The function yy can then be written as y=7uy=7^{u}.
  3. Derivative with Respect to Inner Function: The derivative of yy with respect to uu, using the exponential rule, is dydu=7uln(7)\frac{dy}{du} = 7^u \cdot \ln(7).
  4. Find Derivative of Inner Function: Now we need to find the derivative of uu with respect to xx, which is dudx=36x3+12x2\frac{du}{dx} = 36x^{3} + 12x^{2}.
  5. Apply Chain Rule: Using the chain rule, the derivative of yy with respect to xx is dydx=dydududx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}.
  6. Substitute Expressions: Substitute the expressions for dydu\frac{dy}{du} and dudx\frac{du}{dx} into the chain rule formula to get dydx=(7uln(7))(36x3+12x2)\frac{dy}{dx} = (7^u \cdot \ln(7)) \cdot (36x^{3} + 12x^{2}).
  7. Substitute Back Expression: Now we need to substitute back the expression for uu into the derivative to get dydx\frac{dy}{dx} in terms of xx. So, dydx=(79x4+4x3ln(7))(36x3+12x2)\frac{dy}{dx} = (7^{9x^{4}+4x^{3}} \cdot \ln(7)) \cdot (36x^{3} + 12x^{2}).
  8. Simplify Final Derivative: Simplify the expression to get the final derivative: y=(79x4+4x3ln(7))(36x3+12x2)y' = (7^{9x^{4}+4x^{3}} \cdot \ln(7)) \cdot (36x^{3} + 12x^{2}).

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