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Find the derivative of the following function.

y=7^(3x^(5)-2x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=73x52x4 y=7^{3 x^{5}-2 x^{4}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=73x52x4 y=7^{3 x^{5}-2 x^{4}} \newlineAnswer: y= y^{\prime}=
  1. Identify Function Components: Identify the function and its components.\newlineWe have y=73x52x4y = 7^{3x^{5}-2x^{4}}. This is an exponential function with base 77 and an exponent that is a polynomial in xx.
  2. Apply Chain Rule: Apply the chain rule for derivatives.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is 7u7^u and the inner function is u(x)=3x52x4u(x) = 3x^{5}-2x^{4}.
  3. Differentiate Outer Function: Differentiate the outer function with respect to the inner function.\newlineThe derivative of aua^u with respect to uu is auln(a)a^u \cdot \ln(a), where aa is a constant and uu is a function of xx. Therefore, the derivative of 7u7^u with respect to uu is 7uln(7)7^u \cdot \ln(7).
  4. Differentiate Inner Function: Differentiate the inner function with respect to xx. The inner function u(x)=3x52x4u(x) = 3x^{5}-2x^{4} is a polynomial, and we can differentiate it term by term. The derivative of 3x53x^{5} with respect to xx is 15x415x^{4}, and the derivative of 2x4-2x^{4} with respect to xx is 8x3-8x^{3}. Therefore, the derivative of u(x)u(x) is 15x48x315x^{4} - 8x^{3}.
  5. Combine Using Chain Rule: Combine the results using the chain rule.\newlineThe derivative of yy with respect to xx is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. This gives us y=(73x52x4ln(7))(15x48x3)y' = (7^{3x^{5}-2x^{4}} \cdot \ln(7)) \cdot (15x^{4} - 8x^{3}).
  6. Simplify Expression: Simplify the expression.\newlineWe can leave the derivative in its factored form, as y=(73x52x4ln(7))(15x48x3)y' = (7^{3x^{5}-2x^{4}} \cdot \ln(7)) \cdot (15x^{4} - 8x^{3}), or we can distribute the ln(7)\ln(7) to both terms in the parentheses, but it is not necessary for the final answer.

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