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Find the derivative of the following function.

y=6^(9x^(6)+8x^(5))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=69x6+8x5 y=6^{9 x^{6}+8 x^{5}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=69x6+8x5 y=6^{9 x^{6}+8 x^{5}} \newlineAnswer: y= y^{\prime}=
  1. Identify Function Type and Rule: Identify the type of function and the rule needed to find its derivative.\newlineThe function y=69x6+8x5y = 6^{9x^{6}+8x^{5}} is an exponential function with a variable exponent. To differentiate it, we need to use the chain rule and the fact that the derivative of aua^u with respect to xx is auln(a)ua^u \cdot \ln(a) \cdot u', where uu is a function of xx.
  2. Apply Chain Rule: Apply the chain rule to differentiate the function.\newlineLet u=9x6+8x5u = 9x^{6} + 8x^{5}. Then y=6uy = 6^{u}. The derivative of yy with respect to xx is dydx=d(6u)dx=6uln(6)dudx\frac{dy}{dx} = \frac{d(6^{u})}{dx} = 6^{u} \cdot \ln(6) \cdot \frac{du}{dx}.
  3. Find u Derivative: Find the derivative of uu with respect to xx. We have u=9x6+8x5u = 9x^{6} + 8x^{5}. The derivative of uu with respect to xx is dudx=d(9x6)dx+d(8x5)dx=54x5+40x4\frac{du}{dx} = \frac{d(9x^{6})}{dx} + \frac{d(8x^{5})}{dx} = 54x^{5} + 40x^{4}.
  4. Substitute into dydx\frac{dy}{dx}: Substitute the derivative of uu into the derivative of yy. Now we can substitute dudx\frac{du}{dx} into the expression for dydx\frac{dy}{dx} from Step 22. We get dydx=6(9x6+8x5)ln(6)(54x5+40x4)\frac{dy}{dx} = 6^{(9x^{6}+8x^{5})} \cdot \ln(6) \cdot (54x^{5} + 40x^{4}).
  5. Simplify if Necessary: Simplify the expression if necessary.\newlineThe expression for the derivative is already in its simplest form, so no further simplification is needed.

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