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Find the derivative of the following function.

y=5^(8x^(2))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=58x2 y=5^{8 x^{2}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=58x2 y=5^{8 x^{2}} \newlineAnswer: y= y^{\prime}=
  1. Identify Components: Identify the components of the function.\newlineThe function y=58x2y = 5^{8x^{2}} is an exponential function where the base is a constant (55) and the exponent is a function of xx (8x28x^{2}).
  2. Apply Chain Rule: Apply the chain rule for derivatives.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is 5u5^u and the inner function is u=8x2u = 8x^{2}.
  3. Find Derivative Outer: Find the derivative of the outer function with respect to uu. The derivative of aua^u with respect to uu, where aa is a constant, is auln(a)a^u \cdot \ln(a). Therefore, the derivative of 5u5^u with respect to uu is 5uln(5)5^u \cdot \ln(5).
  4. Find Derivative Inner: Find the derivative of the inner function with respect to xx. The inner function is u=8x2u = 8x^{2}. The derivative of 8x28x^{2} with respect to xx is 16x16x, since ddx(x2)=2x\frac{d}{dx}(x^{2}) = 2x and we have a constant multiple of 88.
  5. Apply Chain Rule: Apply the chain rule using the derivatives from steps 33 and 44.\newlineThe derivative of yy with respect to xx is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. This gives us y=(58x2ln(5))(16x)y' = (5^{8x^{2}} \cdot \ln(5)) \cdot (16x).
  6. Simplify Derivative: Simplify the expression for the derivative.\newliney=16x58x2ln(5)y' = 16x \cdot 5^{8x^{2}} \cdot \ln(5). This is the simplified form of the derivative of the given function.

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