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Find the derivative of the following function.

y=2^(-8x^(5)+2x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=28x5+2x4 y=2^{-8 x^{5}+2 x^{4}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=28x5+2x4 y=2^{-8 x^{5}+2 x^{4}} \newlineAnswer: y= y^{\prime}=
  1. Identify Function Components: Identify the function and its components.\newlineWe have the function y=28x5+2x4y = 2^{-8x^{5} + 2x^{4}}. This is an exponential function with a base of 22 and an exponent that is a polynomial in xx.
  2. Apply Chain Rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is 2u2^u and the inner function is u=8x5+2x4u = -8x^{5} + 2x^{4}.
  3. Differentiate Outer Function: Differentiate the outer function with respect to the inner function uu. The derivative of 2u2^u with respect to uu is (2u)ln(2)(2^u) \cdot \ln(2), where ln(2)\ln(2) is the natural logarithm of 22.
  4. Differentiate Inner Function: Differentiate the inner function u=8x5+2x4u = -8x^{5} + 2x^{4} with respect to xx. The derivative of 8x5-8x^{5} is 40x4-40x^{4}, and the derivative of 2x42x^{4} is 8x38x^{3}. So, the derivative of the inner function uu with respect to xx is u=40x4+8x3u' = -40x^{4} + 8x^{3}.
  5. Apply Chain Rule Multiplication: Apply the chain rule by multiplying the derivatives from Step 33 and Step 44.\newlineThe derivative of yy with respect to xx is y=(28x5+2x4)ln(2)(40x4+8x3)y' = (2^{-8x^{5} + 2x^{4}}) \cdot \ln(2) \cdot (-40x^{4} + 8x^{3}).
  6. Simplify Derivative Expression: Simplify the expression for the derivative.\newliney=(28x5+2x4)ln(2)(40x4+8x3)y' = (2^{-8x^{5} + 2x^{4}}) \cdot \ln(2) \cdot (-40x^{4} + 8x^{3}) can be left as is, or factored to show the common factor of 8x38x^{3}.\newliney=8x3(28x5+2x4)ln(2)(5x+1)y' = 8x^{3} \cdot (2^{-8x^{5} + 2x^{4}}) \cdot \ln(2) \cdot (-5x + 1)

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