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Find the derivative of q(x) q(x) . \newlineq(x)=ln(xe) q(x) = \ln\left(\frac{x}{e}\right) \newlineq(x)= q'\left(x\right) = ______

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Q. Find the derivative of q(x) q(x) . \newlineq(x)=ln(xe) q(x) = \ln\left(\frac{x}{e}\right) \newlineq(x)= q'\left(x\right) = ______
  1. Simplifying q(x): Let's first simplify the function q(x)=ln(xe)q(x) = \ln(\frac{x}{e}). We can use the property of logarithms that ln(ab)=ln(a)ln(b)\ln(\frac{a}{b}) = \ln(a) - \ln(b) to rewrite q(x).\newlineq(x)=ln(x)ln(e)q(x) = \ln(x) - \ln(e)\newlineSince ln(e)\ln(e) is a constant (ln(e)=1\ln(e) = 1), we can simplify further:\newlineq(x)=ln(x)1q(x) = \ln(x) - 1
  2. Finding the derivative of q(x): Now, we need to find the derivative of q(x) with respect to x. The derivative of ln(x)\ln(x) with respect to x is 1x\frac{1}{x}, and the derivative of a constant is 00.\newlineSo, q(x)=ddx[ln(x)1]q'(x) = \frac{d}{dx} [\ln(x) - 1]\newlineq(x)=ddx[ln(x)]ddx[1]q'(x) = \frac{d}{dx} [\ln(x)] - \frac{d}{dx} [1]\newlineq(x)=1x0q'(x) = \frac{1}{x} - 0
  3. Final derivative of q(x): We can now write the final derivative of q(x):\newlineq'(x) = \frac{11}{x}\newlineThis is the derivative of the function q(x) = \ln\left(\frac{x}{e}\right).

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