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Find the derivative of \newlinef(x)=4x(3x4).f(x)=-4x(3^{x^{4}}).

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Q. Find the derivative of \newlinef(x)=4x(3x4).f(x)=-4x(3^{x^{4}}).
  1. Product Rule Explanation: To find the derivative of f(x)=4x(3x4)f(x) = -4x(3^{x^{4}}), we will use the product rule and the chain rule. The product rule states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function.
  2. Derivative of u(x)u(x): Let's denote the two functions as u(x)=4xu(x) = -4x and v(x)=3(x4)v(x) = 3^{(x^{4})}. We will find the derivatives of u(x)u(x) and v(x)v(x) separately.
  3. Derivative of v(x)v(x): The derivative of u(x)=4xu(x) = -4x with respect to xx is u(x)=4u'(x) = -4, since the derivative of xx with respect to xx is 11.
  4. Chain Rule Application: To find the derivative of v(x)=3x4v(x) = 3^{x^{4}}, we will use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  5. Derivative of v(x)v(x): The outer function is g(y)=3yg(y) = 3^y, and the inner function is h(x)=x4h(x) = x^4. The derivative of the outer function with respect to yy is g(y)=3yln(3)g'(y) = 3^y \cdot \ln(3), and the derivative of the inner function with respect to xx is h(x)=4x3h'(x) = 4x^3.
  6. Product Rule Application: Applying the chain rule, the derivative of v(x)v(x) is v(x)=g(h(x))h(x)=3(x4)ln(3)4x3v'(x) = g'(h(x)) \cdot h'(x) = 3^{(x^{4})} \cdot \ln(3) \cdot 4x^{3}.
  7. Simplify Expression: Now we can apply the product rule to find the derivative of f(x)=u(x)v(x)f(x) = u(x)v(x). Using the product rule, f(x)=u(x)v(x)+u(x)v(x)f'(x) = u'(x)v(x) + u(x)v'(x).
  8. Factor Out Common Term: Substituting the derivatives we found, f(x)=(4)(3x4)+(4x)(3x4ln(3)4x3)f'(x) = (-4)(3^{x^{4}}) + (-4x)(3^{x^{4}} \cdot \ln(3) \cdot 4x^3).
  9. Factor Out Common Term: Substituting the derivatives we found, f(x)=(4)(3x4)+(4x)(3x4ln(3)4x3)f'(x) = (-4)(3^{x^{4}}) + (-4x)(3^{x^{4}} \cdot \ln(3) \cdot 4x^3). Simplify the expression to combine like terms. f(x)=43x416x43x4ln(3)f'(x) = -4 \cdot 3^{x^{4}} - 16x^4 \cdot 3^{x^{4}} \cdot \ln(3).
  10. Factor Out Common Term: Substituting the derivatives we found, f(x)=(4)(3x4)+(4x)(3x4ln(3)4x3)f'(x) = (-4)(3^{x^{4}}) + (-4x)(3^{x^{4}} \cdot \ln(3) \cdot 4x^3). Simplify the expression to combine like terms. f(x)=43x416x43x4ln(3)f'(x) = -4 \cdot 3^{x^{4}} - 16x^4 \cdot 3^{x^{4}} \cdot \ln(3). Factor out the common term 3x43^{x^{4}} to get the final derivative. f(x)=3x4(416x4ln(3))f'(x) = 3^{x^{4}} \cdot (-4 - 16x^4 \cdot \ln(3)).

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