Find lim_(x rarr3)f(x) for f(x)=(x^(2)-4)/(11-2x).

Substitute x into function: Substitute the value of x into the function to see if the function is defined at that point. Let's substitute x = 3 into f(x) = (x^2 - 4) / (11 - 2x). f(3) = ((3)^2 - 4) / (11 - 2*3) f(3) = (9 - 4) / (11 - 6) f(3) = 5 / 5 f(3) = 1Calculate f(3): Since the function is defined at x = 3 and there is no indeterminate form, the limit as x approaches 3 is simply the value of the function at x = 3. Therefore, lim_(x -> 3)f(x) = f(3) = 1.

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Find
lim_(x rarr3)f(x) for
f(x)=(x^(2)-4)/(11-2x).

Find $\lim _{x \rightarrow 3} f(x)$ for $f(x)=\frac{x^{2}-4}{11-2 x}$ .

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Calculus

Find derivatives using the chain rule I

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Q. Find

\lim _{x \rightarrow 3} f(x)

for

f(x)=\frac{x^{2}-4}{11-2 x}

Substitute $x$ into function: Substitute the value of $x$ into the function to see if the function is defined at that point. $\newline$ Let's substitute $x = 3$ into $f(x) = \frac{x^2 - 4}{11 - 2x}$ . $\newline$ $f(3) = \frac{(3)^2 - 4}{11 - 2\cdot 3}$ $\newline$ $f(3) = \frac{9 - 4}{11 - 6}$ $\newline$ $f(3) = \frac{5}{5}$ $\newline$ $f(3) = 1$
Calculate $f(3)$ : Since the function is defined at $x = 3$ and there is no indeterminate form, the limit as $x$ approaches $3$ is simply the value of the function at $x = 3$ . Therefore, $\lim_{x \to 3}f(x) = f(3) = 1$ .