Find (d)/(dx)(9cos(-x+1)) Answer:

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Find  (d)/(dx)(9cos(-x+1)) Answer:

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Identify Functions: We need to find the derivative of the function 9cos(-x+1) with respect to x. We will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.Derivative of Outer Function: First, let's identify the outer function and the inner function. The outer function is 9cos(u), where u is the inner function -x+1.Derivative of Inner Function: The derivative of the outer function with respect to u (where u = -x+1) is -9sin(u), because the derivative of cos(u) with respect to u is -sin(u), and we have to multiply by the constant 9.Apply Chain Rule: Now we need to find the derivative of the inner function u = -x+1 with respect to x. The derivative of -x with respect to x is -1, and the derivative of a constant (like +1) is 0. So, the derivative of u with respect to x is -1.Final Derivative: Using the chain rule, we multiply the derivative of the outer function by the derivative of the inner function. This gives us -9sin(u) * (-1).Substitute back the value of u (-x+1) into the derivative. So, the final derivative is -9sin(-x+1) * (-1) which simplifies to 9sin(-x+1).

Find $\frac{d}{d x}(9 \cos (-x+1))$ $\newline$ Answer:

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Find $\frac{d}{d x}(9 \cos (-x+1))$ $\newline$ Answer: