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Find 
(d)/(dx)(7cos 4x)
Answer:

Find ddx(7cos4x) \frac{d}{d x}(7 \cos 4 x) \newlineAnswer:

Full solution

Q. Find ddx(7cos4x) \frac{d}{d x}(7 \cos 4 x) \newlineAnswer:
  1. Identify Function: We need to find the derivative of the function 7cos(4x)7\cos(4x) with respect to xx. We will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. The outer function in this case is 7cos(u)7\cos(u), where u=4xu = 4x, and the inner function is 4x4x.
  2. Differentiate Outer Function: First, we differentiate the outer function with respect to its argument uu. The derivative of cos(u)\cos(u) with respect to uu is sin(u)-\sin(u). Since we have a constant multiple of 77, the derivative of 7cos(u)7\cos(u) with respect to uu is 7sin(u)-7\sin(u).
  3. Differentiate Inner Function: Next, we differentiate the inner function 4x4x with respect to xx. The derivative of 4x4x with respect to xx is 44.
  4. Apply Chain Rule: Now, we apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function. This gives us 7sin(u)×4-7\sin(u) \times 4, where u=4xu = 4x.
  5. Substitute and Simplify: Substitute uu back with 4x4x to get the final derivative. So, the derivative of 7cos(4x)7\cos(4x) with respect to xx is 7sin(4x)×4-7\sin(4x) \times 4.
  6. Substitute and Simplify: Substitute uu back with 4x4x to get the final derivative. So, the derivative of 7cos(4x)7\cos(4x) with respect to xx is 7sin(4x)×4-7\sin(4x) \times 4. Simplify the expression to get the final answer. 7sin(4x)×4=28sin(4x)-7\sin(4x) \times 4 = -28\sin(4x).

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