Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor the following expression completely.

x^(4)-4x^(2)-8x^(3)+32 x+12x^(2)-48
Answer:

Factor the following expression completely.\newlinex44x28x3+32x+12x248 x^{4}-4 x^{2}-8 x^{3}+32 x+12 x^{2}-48 \newlineAnswer:

Full solution

Q. Factor the following expression completely.\newlinex44x28x3+32x+12x248 x^{4}-4 x^{2}-8 x^{3}+32 x+12 x^{2}-48 \newlineAnswer:
  1. Rewrite and Combine Terms: First, let's rewrite the expression in descending order of the powers of xx:x48x3+(12x24x2)+32x48x^4 - 8x^3 + (12x^2 - 4x^2) + 32x - 48Now, combine like terms:x48x3+8x2+32x48x^4 - 8x^3 + 8x^2 + 32x - 48
  2. Factor Out Common Factors: Next, we look for common factors in groups of terms. We can group the terms as follows:\newline(x48x3)+(8x2+32x)48 (x^4 - 8x^3) + (8x^2 + 32x) - 48 \newlineNow, factor out the greatest common factor from each group:\newlinex3(x8)+8x(x+4)48 x^3(x - 8) + 8x(x + 4) - 48
  3. Factor by Grouping: We notice that there is no common factor that we can factor out from all terms. However, we can try to factor by grouping. To do this, we need to find two numbers that multiply to give the product of the coefficient of x4x^4 (1-1) and the constant term (48-48), and add up to the coefficient of x2x^2 (88). These numbers are 1212 and 4-4. So we rewrite the middle terms using 1212 and 4-4: x3(x8)+12x(x8)4(x8)x^3(x - 8) + 12x(x - 8) - 4(x - 8)
  4. Factor Out Common Factor: Now, we can factor out the common factor (x8)(x - 8) from the terms: (x8)(x3+12x4)(x - 8)(x^3 + 12x - 4)
  5. Correct Mistake: We now have a quadratic in the form of x3+12x4x^3 + 12x - 4. This does not factor easily, and it seems we have made a mistake in the previous step because we should have a quadratic term, not a cubic term. We need to go back and correct this error.

More problems from Find derivatives of using multiple formulae