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Factor the following expression completely.

x^(4)-4x^(2)-3x^(3)+12 x+2x^(2)-8
Answer:

Factor the following expression completely.\newlinex44x23x3+12x+2x28 x^{4}-4 x^{2}-3 x^{3}+12 x+2 x^{2}-8 \newlineAnswer:

Full solution

Q. Factor the following expression completely.\newlinex44x23x3+12x+2x28 x^{4}-4 x^{2}-3 x^{3}+12 x+2 x^{2}-8 \newlineAnswer:
  1. Rearrange and Combine Terms: First, we should rearrange the terms of the polynomial in descending order of the powers of xx.x43x34x2+2x2+12x8x^{4} - 3x^{3} - 4x^{2} + 2x^{2} + 12x - 8Now, combine like terms.x43x32x2+12x8x^{4} - 3x^{3} - 2x^{2} + 12x - 8
  2. Factor Out Common Factors: Next, we look for common factors in groups of terms. We can group the terms as follows:\newlinex43x3x^{4} - 3x^{3} + 2x2+12x-2x^{2} + 12x - 88\newlineNow, factor out the greatest common factor from each group.\newlinex3(x3)x^{3}(x - 3) - 2x(x6)2x(x - 6) - 88
  3. Explore Different Grouping: We notice that there is no common factor that we can factor out from all terms. However, we can look for a pattern or try to factor by grouping in a different way. Let's try to factor by grouping in pairs differently:\newline(x44x2)(3x312x)+(2x28) (x^{4} - 4x^{2}) - (3x^{3} - 12x) + (2x^{2} - 8) \newlineNow, factor out the greatest common factor from each pair.\newlinex2(x24)3x(x24)+2(x24) x^{2}(x^{2} - 4) - 3x(x^{2} - 4) + 2(x^{2} - 4)
  4. Factor Quadratic: We can see that (x24)(x^{2} - 4) is a common factor in all three groups. Let's factor that out.(x24)(x23x+2)(x^{2} - 4)(x^{2} - 3x + 2)
  5. Factor Difference of Squares: Now, we need to factor the quadratic x23x+2x^{2} - 3x + 2. This is a simple quadratic that can be factored into two binomials.\newline(x1)(x2)(x - 1)(x - 2)
  6. Combine All Factors: The factor (x24)(x^{2} - 4) is a difference of squares, which can be factored further.(x+2)(x2)(x + 2)(x - 2)
  7. Final Factored Expression: Now, we combine all the factors we have found to write the completely factored expression. x + \(2)(x - 22)(x - 11)(x - 22)\
  8. Final Factored Expression: Now, we combine all the factors we have found to write the completely factored expression.\newline(x+2)(x2)(x1)(x2)(x + 2)(x - 2)(x - 1)(x - 2)We notice that (x2)(x - 2) appears twice, so we can write it as a square.\newline(x+2)(x2)2(x1)(x + 2)(x - 2)^2(x - 1)\newlineThis is the completely factored form of the given expression.

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