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Factor the expression completely.

x^(4)-10x^(2)+21
Answer:

Factor the expression completely.\newlinex410x2+21 x^{4}-10 x^{2}+21 \newlineAnswer:

Full solution

Q. Factor the expression completely.\newlinex410x2+21 x^{4}-10 x^{2}+21 \newlineAnswer:
  1. Identify Type and Strategy: Identify the type of polynomial and look for a common factoring strategy.\newlineThis is a quadratic in form, with x4x^4 as the "squared" term, x2x^2 as the "linear" term, and 2121 as the constant. We can treat x2x^2 as a single variable and factor it as if it were a quadratic equation.
  2. Set Up Factoring Format: Set up the expression in a factoring format.\newlineWe are looking for two binomials that multiply to give x410x2+21x^4 - 10x^2 + 21. The general form will be (x2a)(x2b)(x^2 - a)(x^2 - b), where aa and bb are numbers that multiply to 2121 and add up to 1010.
  3. Find Factors and Sum: Find the factors of 2121 that add up to 1010. The factors of 2121 are 11, 33, 77, and 2121. The pair that adds up to 1010 is 33 and 77.
  4. Write Factored Form: Write the factored form using the factors found.\newlineThe factored form of the expression is (x23)(x27)(x^2 - 3)(x^2 - 7).
  5. Check Factoring: Check the factoring by expanding the binomials.\newline(x23)(x27)=x47x23x2+21=x410x2+21.(x^2 - 3)(x^2 - 7) = x^4 - 7x^2 - 3x^2 + 21 = x^4 - 10x^2 + 21.\newlineThe expanded form matches the original expression, so the factoring is correct.

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