Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor the expression completely.

x^(2)y-x^(5)
Answer:

Factor the expression completely.\newlinex2yx5 x^{2} y-x^{5} \newlineAnswer:

Full solution

Q. Factor the expression completely.\newlinex2yx5 x^{2} y-x^{5} \newlineAnswer:
  1. Identify Common Factor: Identify the common factor in both terms of the expression x2yx5x^{2}y - x^{5}. Both terms have an 'xx' raised to a power, so we can factor out the lowest power of 'xx' which is x2x^{2}.
  2. Factor Out Common Factor: Factor out the common factor x2x^{2} from the expression.\newlinex2yx5=x2(yx3)x^{2}y - x^{5} = x^{2}(y - x^{3})
  3. Check for Further Factoring: Check to see if the remaining expression inside the parentheses can be factored further.\newlineThe expression inside the parentheses is yx3y - x^{3}, which does not have a common factor and is not a special product that can be factored further.

More problems from Solve equations with variable exponents

QuestionGet tutor helpright-arrow

Posted 7 months ago

QuestionGet tutor helpright-arrow

Posted 9 months ago