Factor t^(3)-k^(3) completely. Answer:

Use Difference of Cubes Formula: To factor the difference of cubes t^3 - k^3, we use the formula a^3 - b^3 = (a - b)(a^2 + ab + b^2), where a = t and b = k.Apply the Formula: Applying the formula, we get: t^3 - k^3 = (t - k)(t^2 + tk + k^2).Check for Common Factors: We check for any common factors in the terms t^2, tk, and k^2. There are none, so the factorization is complete.Final Answer: The final answer is the factorization of t^3 - k^3, which is (t - k)(t^2 + tk + k^2).

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Factor $t^{3}-k^{3}$ completely. $\newline$ Answer:

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Calculus

Find derivatives of using multiple formulae

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Q. Factor

t^{3}-k^{3}

completely.

\newline

Answer:

Use Difference of Cubes Formula: To factor the difference of cubes $t^3 - k^3$ , we use the formula $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$ , where $a = t$ and $b = k$ .
Apply the Formula: Applying the formula, we get: $t^3 - k^3 = (t - k)(t^2 + tk + k^2)$ .
Check for Common Factors: We check for any common factors in the terms $t^2$ , $tk$ , and $k^2$ . There are none, so the factorization is complete.
Final Answer: The final answer is the factorization of $t^3 - k^3$ , which is $(t - k)(t^2 + tk + k^2)$ .