Factor completely: (x+9)(3x-1)-(x+9)^(2)(2x+3) Answer:

Identify Common Factor: Identify the common factor in both terms of the expression. The common factor is (x+9).Factor Out Common Factor: Factor out the common factor (x+9) from both terms. (x+9)[(3x-1)-(x+9)(2x+3)]Distribute Negative Sign: Distribute the negative sign inside the second term. (x+9)[(3x-1)-(x+9)(2x+3)] = (x+9)[(3x-1)-(2x^2+3x+18x+27)]Combine Like Terms: Combine like terms inside the brackets. (x+9)[(3x-1)-(2x^2+3x+18x+27)] = (x+9)[3x-1-2x^2-3x-18x-27]Simplify Expression: Simplify the expression inside the brackets. (x+9)[3x-1-2x^2-3x-18x-27] = (x+9)[-2x^2-18x+3x-1-27]Combine X Terms: Combine the x terms inside the brackets. (x+9)[-2x^2-18x+3x-1-27] = (x+9)[-2x^2-15x-28]Write Final Form: Write the final factored form. The completely factored form is (x+9)(-2x^2-15x-28).

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Factor completely:

(x+9)(3x-1)-(x+9)^(2)(2x+3)
Answer:

Factor completely: $\newline$ $(x+9)(3 x-1)-(x+9)^{2}(2 x+3)$ $\newline$ Answer:

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Math Problems

Grade 8

Powers with negative bases

Full solution

Q. Factor completely:

\newline

(x+9)(3 x-1)-(x+9)^{2}(2 x+3)

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms of the expression. $\newline$ The common factor is $(x+9)$ .
Factor Out Common Factor: Factor out the common factor $(x+9)$ from both terms. $(x+9)[(3x-1)-(x+9)(2x+3)]$
Distribute Negative Sign: Distribute the negative sign inside the second term. $\newline$ $(x+9)[(3x-1)-(x+9)(2x+3)] = (x+9)[(3x-1)-(2x^2+3x+18x+27)]$
Combine Like Terms: Combine like terms inside the brackets. $\newline$ $(x+9)[(3x-1)-(2x^2+3x+18x+27)] = (x+9)[3x-1-2x^2-3x-18x-27]$
Simplify Expression: Simplify the expression inside the brackets. $\newline$ $(x+9)[3x-1-2x^2-3x-18x-27] = (x+9)[-2x^2-18x+3x-1-27]$
Combine X Terms: Combine the $x$ terms inside the brackets. $(x+9)[-2x^2-18x+3x-1-27] = (x+9)[-2x^2-15x-28]$
Write Final Form: Write the final factored form. $\newline$ The completely factored form is $(x+9)(-2x^2-15x-28)$ .