Factor completely: (x-8)^(6)-2(x-8)^(5) Answer:

Recognize common factor: Recognize the common factor. In the expression (x-8)^(6)-2(x-8)^(5), both terms have a common factor of (x-8)^(5).Factor out common factor: Factor out the common factor. Factor (x-8)^(5) out of each term. (x-8)^(6)-2(x-8)^(5) = (x-8)^(5) * [(x-8) - 2]Simplify inside brackets: Simplify the expression inside the brackets. Subtract 2 from (x-8) to get (x-10). (x-8)^(5) * [(x-8) - 2] = (x-8)^(5) * (x-10)Write final factored form: Write the final factored form. The completely factored form of the expression is (x-8)^(5) * (x-10).

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Factor completely:

(x-8)^(6)-2(x-8)^(5)
Answer:

Factor completely: $\newline$ $(x-8)^{6}-2(x-8)^{5}$ $\newline$ Answer:

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Math Problems

Grade 8

Powers with negative bases

Full solution

Q. Factor completely:

\newline

(x-8)^{6}-2(x-8)^{5}

\newline

Answer:

Recognize common factor: Recognize the common factor. $\newline$ In the expression $(x-8)^{6}-2(x-8)^{5}$ , both terms have a common factor of $(x-8)^{5}$ .
Factor out common factor: Factor out the common factor. $\newline$ Factor $(x-8)^{5}$ out of each term. $\newline$ $(x-8)^{6}-2(x-8)^{5} = (x-8)^{5} \cdot [(x-8) - 2]$
Simplify inside brackets: Simplify the expression inside the brackets. $\newline$ Subtract $2$ from $(x-8)$ to get $(x-10)$ . $\newline$ $(x-8)^{5} \cdot [(x-8) - 2] = (x-8)^{5} \cdot (x-10)$
Write final factored form: Write the final factored form. $\newline$ The completely factored form of the expression is $(x-8)^{5} \times (x-10)$ .