Factor completely: x^(2)(x+3)-7x(x+3)+6(x+3) Answer:

Identify Common Factor: Identify the common factor in all terms. The expression is x^(2)(x+3)-7x(x+3)+6(x+3). Each term contains the factor (x+3).Factor Out Common Factor: Factor out the common factor (x+3). We can write the expression as (x+3)(x^2 - 7x + 6).Factor Quadratic Expression: Factor the quadratic expression. The quadratic expression x^2 - 7x + 6 can be factored into (x - 1)(x - 6) because (x - 1)(x - 6) = x^2 - 6x - x + 6 = x^2 - 7x + 6.Write Completely Factored Form: Write the completely factored form. The completely factored form of the original expression is (x+3)(x-1)(x-6).

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Factor completely:

x^(2)(x+3)-7x(x+3)+6(x+3)
Answer:

Factor completely: $\newline$ $x^{2}(x+3)-7 x(x+3)+6(x+3)$ $\newline$ Answer:

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Math Problems

Grade 8

Powers with negative bases

Full solution

Q. Factor completely:

\newline

x^{2}(x+3)-7 x(x+3)+6(x+3)

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Answer:

Identify Common Factor: Identify the common factor in all terms. $\newline$ The expression is $x^{2}(x+3)-7x(x+3)+6(x+3)$ . Each term contains the factor $(x+3)$ .
Factor Out Common Factor: Factor out the common factor $(x+3)$ . We can write the expression as $(x+3)(x^2 - 7x + 6)$ .
Factor Quadratic Expression: Factor the quadratic expression. $\newline$ The quadratic expression $x^2 - 7x + 6$ can be factored into $(x - 1)(x - 6)$ because $(x - 1)(x - 6) = x^2 - 6x - x + 6 = x^2 - 7x + 6$ .
Write Completely Factored Form: Write the completely factored form. $\newline$ The completely factored form of the original expression is $(x+3)(x-1)(x-6)$ .