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Factor completely:

x^(2)(x^(2)-10)-5x(x^(2)-10)-14(x^(2)-10)
Answer:

Factor completely:\newlinex2(x210)5x(x210)14(x210) x^{2}\left(x^{2}-10\right)-5 x\left(x^{2}-10\right)-14\left(x^{2}-10\right) \newlineAnswer:

Full solution

Q. Factor completely:\newlinex2(x210)5x(x210)14(x210) x^{2}\left(x^{2}-10\right)-5 x\left(x^{2}-10\right)-14\left(x^{2}-10\right) \newlineAnswer:
  1. Identify Common Factor: Identify the common factor in all terms of the expression.\newlineThe common factor is (x210)(x^2 - 10).
  2. Factor Out Common Factor: Factor out the common factor from each term.\newlinex2(x210)5x(x210)14(x210)=(x210)(x25x14)x^2(x^2 - 10) - 5x(x^2 - 10) - 14(x^2 - 10) = (x^2 - 10)(x^2 - 5x - 14)
  3. Factor Quadratic Expression: Now, factor the quadratic expression x25x14x^2 - 5x - 14. To factor the quadratic, we look for two numbers that multiply to 14-14 and add up to 5-5. These numbers are 7-7 and +2+2.
  4. Write Factored Form: Write the factored form of the quadratic expression.\newline(x25x14)=(x7)(x+2)(x^2 - 5x - 14) = (x - 7)(x + 2)
  5. Combine Factored Expressions: Combine the factored quadratic with the common factor that was factored out earlier.\newline(x210)(x25x14)=(x210)(x7)(x+2)(x^2 - 10)(x^2 - 5x - 14) = (x^2 - 10)(x - 7)(x + 2)

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