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Factor completely:

x^(2)(x+1)+3x(x+1)-70(x+1)
Answer:

Factor completely:\newlinex2(x+1)+3x(x+1)70(x+1) x^{2}(x+1)+3 x(x+1)-70(x+1) \newlineAnswer:

Full solution

Q. Factor completely:\newlinex2(x+1)+3x(x+1)70(x+1) x^{2}(x+1)+3 x(x+1)-70(x+1) \newlineAnswer:
  1. Factor out common term: First, notice that each term in the expression contains a common factor of (x+1)(x+1). We can factor out (x+1)(x+1) from each term.\newlinex2(x+1)+3x(x+1)70(x+1)=(x+1)(x2+3x70)x^{2}(x+1)+3x(x+1)-70(x+1) = (x+1)(x^2 + 3x - 70)
  2. Factor quadratic expression: Now we need to factor the quadratic expression x2+3x70x^2 + 3x - 70. We look for two numbers that multiply to 70-70 and add up to 33. These numbers are 1010 and 7-7. \newlinex2+3x70=(x+10)(x7)x^2 + 3x - 70 = (x + 10)(x - 7)
  3. Combine factored parts: We can now write the completely factored form of the original expression by combining the factored parts.\newline(x+1)(x2+3x70)=(x+1)(x+10)(x7)(x+1)(x^2 + 3x - 70) = (x+1)(x + 10)(x - 7)

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