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Factor completely:

x^(2)(4x+5)-x(4x+5)-30(4x+5)
Answer:

Factor completely:\newlinex2(4x+5)x(4x+5)30(4x+5) x^{2}(4 x+5)-x(4 x+5)-30(4 x+5) \newlineAnswer:

Full solution

Q. Factor completely:\newlinex2(4x+5)x(4x+5)30(4x+5) x^{2}(4 x+5)-x(4 x+5)-30(4 x+5) \newlineAnswer:
  1. Identify Common Factor: Identify the common factor in all three terms of the expression.\newlineThe common factor is (4x+5)(4x+5).
  2. Factor Out Common Factor: Factor out the common factor (4x+5)(4x+5) from each term.x2(4x+5)x(4x+5)30(4x+5)=(4x+5)(x2x30)x^{2}(4x+5)-x(4x+5)-30(4x+5) = (4x+5)(x^2 - x - 30)
  3. Factor Quadratic Expression: Now, factor the quadratic expression x2x30x^2 - x - 30. We look for two numbers that multiply to 30-30 and add up to 1-1 (the coefficient of xx). The numbers 6-6 and +5+5 satisfy these conditions.
  4. Write Factored Form: Write the factored form of the quadratic expression using the numbers found in the previous step. x2x30=(x6)(x+5)x^2 - x - 30 = (x - 6)(x + 5)
  5. Combine Factored Expressions: Combine the factored quadratic with the previously factored out common factor.\newline(4x+5)(x2x30)=(4x+5)(x6)(x+5)(4x+5)(x^2 - x - 30) = (4x+5)(x - 6)(x + 5)

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