Identify Factoring Technique: We are looking to factor the polynomial 8x8−x4a4−9a8. To start, we can try to identify a common pattern or structure in the polynomial that might suggest a particular factoring technique. One technique that might be useful here is factoring by grouping, since we have three terms. We can also look for a common factor in all terms, but there is none in this case. Let's proceed with factoring by grouping.
Grouping Terms: We can group the terms as follows: 8x8−x4a4 - 9a8. Now we will look for common factors within each group. The first group has a common factor of x4, and the second group is a single term which is a perfect square.
Factor Out Common Factor: Factoring out the common factor of x4 from the first group gives us x4(8x4−a4). The second group is already a perfect square, −9a8, which can be written as −(3a4)2. Now our expression looks like this: x4(8x4−a4)−(3a4)2.
Apply Difference of Squares: We notice that the expression inside the parentheses, 8x4−a4, is a difference of squares since 8x4 is (2x2)2 and a4 is (a2)2. The difference of squares can be factored as (A2−B2)=(A+B)(A−B). Applying this to 8x4−a4, we get (2x2)2−(a2)2=(2x2+a2)(2x2−a2).
Correct Error: Now we substitute back into our expression with the factored form of 8x4−a4. We get x4((2x2+a2)(2x2−a2))−(3a4)2. However, we made a mistake in the previous step; we did not correctly apply the difference of squares to the term −9a8. The correct factorization of −9a8 should be −((3a4)2), which is already in the factored form as a difference of squares. We need to correct this error.
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