Factor completely: (5x+1)^(2)-(3x+7)^(2) Answer:

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Factor completely:  (5x+1)^(2)-(3x+7)^(2) Answer:

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Recognize as difference of squares: Recognize the expression as a difference of squares. The given expression is in the form of a^2 - b^2, which is a difference of squares. The difference of squares can be factored using the identity a^2 - b^2 = (a + b)(a - b). Here, a = (5x+1) and b = (3x+7).Apply identity: Apply the difference of squares identity. Using the identity from Step 1, we can write the expression as: (5x+1 + 3x+7)(5x+1 - 3x-7)Simplify each factor: Simplify each factor. Now we simplify the expressions inside the parentheses. First factor: (5x+1 + 3x+7) = (5x + 3x) + (1 + 7) = 8x + 8 Second factor: (5x+1 - 3x-7) = (5x - 3x) + (1 - 7) = 2x - 6Factor out common terms: Factor out common terms if possible. Looking at the factors 8x + 8 and 2x - 6, we can factor out common terms. First factor: 8x + 8 can be factored as 8(x + 1) Second factor: 2x - 6 can be factored as 2(x - 3)Write final factored form: Write the final factored form. The completely factored form of the expression is: 8(x + 1) * 2(x - 3)Combine the constants: Combine the constants. Multiplying the constants 8 and 2, we get 16. The final factored form is: 16(x + 1)(x - 3)

Factor completely: $\newline$ $(5 x+1)^{2}-(3 x+7)^{2}$ $\newline$ Answer:

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Factor completely:\newline(5x+1)2−(3x+7)2 (5 x+1)^{2}-(3 x+7)^{2} (5x+1)2−(3x+7)2\newlineAnswer:

Factor completely: $\newline$ $(5 x+1)^{2}-(3 x+7)^{2}$ $\newline$ Answer: