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Factor completely:

4z^(12)-5z^(6)v^(2)-9v^(4)
Answer:

Factor completely:\newline4z125z6v29v4 4 z^{12}-5 z^{6} v^{2}-9 v^{4} \newlineAnswer:

Full solution

Q. Factor completely:\newline4z125z6v29v4 4 z^{12}-5 z^{6} v^{2}-9 v^{4} \newlineAnswer:
  1. Identify common factor: Identify the common factor in the polynomial.\newlineThe polynomial 4z125z6v29v44z^{12}-5z^{6}v^{2}-9v^{4} does not have a common factor across all terms, but we can observe that each term is a multiple of a power of zz or vv. We will look for a pattern or a common binomial factor that might help us factor by grouping or another method.
  2. Pattern or grouping: Look for a pattern or grouping method.\newlineWe can try to factor by grouping, which involves rearranging the terms and factoring out the greatest common factor from each group. However, in this case, there is no clear grouping that will simplify the polynomial. Instead, we notice that the polynomial is a quadratic in form with respect to z6z^6. Let's rewrite the polynomial in terms of u=z6u = z^6.
  3. Substitute and rewrite: Substitute uu for z6z^6 and rewrite the polynomial.\newlineLet u=z6u = z^6. Then the polynomial becomes 4u25uv29v44u^2 - 5uv^2 - 9v^4. This is a quadratic in uu, which we can attempt to factor.
  4. Factor quadratic in \newlineuu: Factor the quadratic in \newlineuu.\newlineWe are looking for two numbers that multiply to \newline(4)(9v4)=36v4(4)(-9v^4) = -36v^4 and add up to \newline5v2-5v^2. These numbers are \newline9v2-9v^2 and \newline4v24v^2. We can now rewrite the middle term \newline5uv2-5uv^2 as \newline9uv2+4uv2-9uv^2 + 4uv^2 and factor by grouping.
  5. Factor by grouping: Factor by grouping.\newlineRewrite the quadratic as 4u29uv2+4uv29v44u^2 - 9uv^2 + 4uv^2 - 9v^4. Now, group the terms:\newline(4u29uv2)+(4uv29v4)(4u^2 - 9uv^2) + (4uv^2 - 9v^4)\newlineFactor out the greatest common factor from each group:\newlineu(4u9v2)+v2(4u9v2)u(4u - 9v^2) + v^2(4u - 9v^2)\newlineNow we can factor out the common binomial factor (4u9v2)(4u - 9v^2):\newline$(u + v^\(2\))(\(4\)u - \(9\)v^\(2\))
  6. Substitute back in: Substitute \(z^6\) back in for \(u\).\(\newline\)Replace \(u\) with \(z^6\) in the factored form:\(\newline\)\((z^6 + v^2)(4z^6 - 9v^2)\)\(\newline\)This is the completely factored form of the original polynomial.

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