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Factor completely.

-4x^(4)+48x^(3)+52x^(2)
Answer:

Factor completely.\newline4x4+48x3+52x2 -4 x^{4}+48 x^{3}+52 x^{2} \newlineAnswer:

Full solution

Q. Factor completely.\newline4x4+48x3+52x2 -4 x^{4}+48 x^{3}+52 x^{2} \newlineAnswer:
  1. Identify Common Factors: First, we look for common factors in all terms of the polynomial 4x4+48x3+52x2-4x^{4}+48x^{3}+52x^{2}.\newlineWe can see that each term has a factor of 4x24x^2.\newlineLet's factor out 4x24x^2 from each term.\newline4x4+48x3+52x2=4x2(x2+12x+13)-4x^{4}+48x^{3}+52x^{2} = 4x^2(-x^2 + 12x + 13)
  2. Factor Out 4x24x^2: Now, we need to factor the quadratic equation inside the parentheses, which is x2+12x+13-x^2 + 12x + 13. We look for two numbers that multiply to 1×13=13-1\times13=-13 and add up to 1212. The numbers that satisfy these conditions are 1313 and 1-1. So, we can write the quadratic as (x+13)(x+1)(-x + 13)(x + 1).
  3. Factor Quadratic Equation: Now we combine the factored out part with the factored quadratic.\newlineThe complete factorization of the polynomial is 4x2(x+13)(x+1)4x^2(-x + 13)(x + 1).

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