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Factor completely:

3x^(3)-36x^(2)+96 x
Answer:

Factor completely:\newline3x336x2+96x 3 x^{3}-36 x^{2}+96 x \newlineAnswer:

Full solution

Q. Factor completely:\newline3x336x2+96x 3 x^{3}-36 x^{2}+96 x \newlineAnswer:
  1. Identify Common Factors: Identify common factors in all terms.\newlineThe polynomial is 3x336x2+96x3x^{3} - 36x^{2} + 96x. We can see that each term has a common factor of 3x3x. We will factor out 3x3x from each term.\newlineCalculation: 3x(x212x+32)3x(x^2 - 12x + 32)
  2. Factor Quadratic Expression: Factor the quadratic expression.\newlineWe now have the quadratic expression x212x+32x^2 - 12x + 32, which we need to factor. We are looking for two numbers that multiply to 3232 and add up to 12-12.\newlineCalculation: The numbers are 8-8 and 4-4 because (8)×(4)=32(-8) \times (-4) = 32 and (8)+(4)=12(-8) + (-4) = -12.
  3. Write Factored Form: Write the factored form of the quadratic expression.\newlineUsing the numbers found in Step 22, we can write the quadratic expression as (x8)(x4)(x - 8)(x - 4).\newlineCalculation: x212x+32=(x8)(x4)x^2 - 12x + 32 = (x - 8)(x - 4)
  4. Combine Factored Quadratic: Combine the factored quadratic with the common factor factored out in Step 11.\newlineWe now multiply the common factor 3x3x by the factored quadratic expression to get the completely factored form of the original polynomial.\newlineCalculation: 3x(x8)(x4)3x(x - 8)(x - 4)

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