Factor completely: 2x^(3)-14x^(2)+12 x Answer:

Identify Common Factor: First, we look for a common factor in all terms of the polynomial 2x^3 - 14x^2 + 12x. The common factor is 2x, as it divides evenly into each term. We factor out 2x from each term. 2x^3 - 14x^2 + 12x = 2x(x^2 - 7x + 6)Factor Out 2x: Now we need to factor the quadratic equation x^2 - 7x + 6. We look for two numbers that multiply to 6 and add up to -7. The numbers -6 and -1 satisfy these conditions. So we can write x^2 - 7x + 6 as (x - 6)(x - 1).Factor Quadratic Equation: We combine the factored out 2x with the factored quadratic to get the final factored form of the polynomial. 2x(x^2 - 7x + 6) = 2x(x - 6)(x - 1) This is the completely factored form of the polynomial.

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Factor completely:

2x^(3)-14x^(2)+12 x
Answer:

Factor completely: $\newline$ $2 x^{3}-14 x^{2}+12 x$ $\newline$ Answer:

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Q. Factor completely:

\newline

2 x^{3}-14 x^{2}+12 x

\newline

Answer:

Identify Common Factor: First, we look for a common factor in all terms of the polynomial $2x^3 - 14x^2 + 12x$ . The common factor is $2x$ , as it divides evenly into each term. We factor out $2x$ from each term. $2x^3 - 14x^2 + 12x = 2x(x^2 - 7x + 6)$
Factor Out $2x$ : Now we need to factor the quadratic equation $x^2 - 7x + 6$ . We look for two numbers that multiply to $6$ and add up to $-7$ . The numbers $-6$ and $-1$ satisfy these conditions. So we can write $x^2 - 7x + 6$ as $(x - 6)(x - 1)$ .
Factor Quadratic Equation: We combine the factored out $2x$ with the factored quadratic to get the final factored form of the polynomial. $\newline$ $2x(x^2 - 7x + 6) = 2x(x - 6)(x - 1)$ $\newline$ This is the completely factored form of the polynomial.