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Factor completely.

-23x^(2)y^(3)z^(3)+21 z
Answer:

Factor completely.\newline23x2y3z3+21z -23 x^{2} y^{3} z^{3}+21 z \newlineAnswer:

Full solution

Q. Factor completely.\newline23x2y3z3+21z -23 x^{2} y^{3} z^{3}+21 z \newlineAnswer:
  1. Identify GCF: Identify the greatest common factor (GCF) of the terms in the expression.\newlineThe terms 23x2y3z3-23x^{2}y^{3}z^{3} and 21z21z have a common factor of zz.
  2. Factor out GCF: Factor out the GCF from each term in the expression.\newlineThe GCF zz is factored out, resulting in z(23x2y3z2+21)z(-23x^{2}y^{3}z^{2} + 21).
  3. Find common factors: Look for any other common factors in the remaining expression inside the parentheses.\newlineThe terms 23x2y3z2-23x^{2}y^{3}z^{2} and 2121 do not have any other common factors.
  4. Check for further factorization: Check if the expression inside the parentheses can be factored further.\newlineThe expression 23x2y3z2+21-23x^{2}y^{3}z^{2} + 21 is not factorable since 2323 is a prime number and does not divide 2121.
  5. Write final factored form: Write down the final factored form of the expression.\newlineThe completely factored form of the expression is z(23x2y3z2+21)z(-23x^{2}y^{3}z^{2} + 21).

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