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Factor completely:

20 x+x^(2)-x^(3)
Answer:

Factor completely:\newline20x+x2x3 20 x+x^{2}-x^{3} \newlineAnswer:

Full solution

Q. Factor completely:\newline20x+x2x3 20 x+x^{2}-x^{3} \newlineAnswer:
  1. Factor out 'x': First, we should look for any common factors in all terms of the polynomial 20x+x2x320x + x^2 - x^3.\newlineWe can see that each term has an 'x' in it, so we can factor out an 'x' from the entire polynomial.\newlineCalculation: x(20+xx2)x(20 + x - x^2)
  2. Rearrange terms in descending order: Now we have x(20+xx2)x(20 + x - x^2). We should rearrange the terms inside the parentheses in descending order of the powers of xx.\newlineCalculation: x(x2+x+20)x(-x^2 + x + 20)
  3. Factor quadratic expression: Next, we need to factor the quadratic expression x2+x+20-x^2 + x + 20. To do this, we look for two numbers that multiply to 20-20 (the product of the coefficient of x2x^2, which is 1-1, and the constant term, which is 2020) and add up to 11 (the coefficient of xx).\newlineThe numbers that satisfy these conditions are 55 and 4-4.\newlineCalculation: x2+x+20=(x2x20)=(x5)(x+4)-x^2 + x + 20 = -(x^2 - x - 20) = -(x - 5)(x + 4)
  4. Combine factored terms: Finally, we combine the factored quadratic with the xx we factored out in the first step.\newlineCalculation: x(x5)(x+4)=x(x5)(x+4)x \cdot -(x - 5)(x + 4) = -x(x - 5)(x + 4)

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