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f(x)={[-(x-2)^(2)+3," for ",x < 2],[-3," for ",x=2],[-2x+7," for ",2 < x <= 6]:}
Find 
f(4)
Answer:

\[ f(x)=\left\{\begin{array}{lll} -(x-2)^{2}+3 & \text { for } & x<2 \\ -3 & \text { for } & x=2 \\ -2 x+7 & \text { for } & 2

Full solution

Q. f(x)={(x2)2+3 for x<23 for x=22x+7 for 2<x6 f(x)=\left\{\begin{array}{lll} -(x-2)^{2}+3 & \text { for } & x<2 \\ -3 & \text { for } & x=2 \\ -2 x+7 & \text { for } & 2<x \leq 6 \end{array}\right. \newlineFind f(4) f(4) \newlineAnswer:\newline
  1. Determine x=4x = 4: Determine which piece of the piecewise function applies to x=4x = 4.\newlineThe function f(x)f(x) is defined by three pieces:\newline- (x2)2+3- (x - 2)^2 + 3 for x < 2\newline- 3-3 for x=2x = 2\newline- 2x+7-2x + 7 for 2 < x \leq 6\newlineSince 44 is greater than x=4x = 400 and less than or equal to x=4x = 411, the third piece of the function applies.
  2. Substitute x=4x = 4: Substitute x=4x = 4 into the third piece of the function.\newlineThe third piece of the function is 2x+7-2x + 7. We substitute x=4x = 4 into this expression to find f(4)f(4).\newlinef(4)=2(4)+7f(4) = -2(4) + 7
  3. Calculate f(4)f(4): Calculate the value of f(4)f(4).
    f(4)=2(4)+7f(4) = -2(4) + 7
    f(4)=8+7f(4) = -8 + 7
    f(4)=1f(4) = -1