f(t)=1,000(161)4tWhich of the following is an equivalent form of the function f in which the base of the exponent is 21 ?Choose 1 answer:(A) f(t)=125(21)4t(B) f(t)=1,000(21)t(C) f(t)=1,000(21)2t(D) f(t)=1,000(21)4t
Q. f(t)=1,000(161)4tWhich of the following is an equivalent form of the function f in which the base of the exponent is 21 ?Choose 1 answer:(A) f(t)=125(21)4t(B) f(t)=1,000(21)t(C) f(t)=1,000(21)2t(D) f(t)=1,000(21)4t
Given Function Conversion: We are given the function f(t)=1,000×(161)4t. We need to express this function with a base of 21 for the exponent.First, let's express 161 as a power of 21.161 is the same as 214 because 214=161.
Substitute Power of (1/2): Now, we can substitute (1)/(2)4 back into the original function for (1)/(16). So, f(t) becomes f(t)=1,000×((1)/(2)4)(t)/(4).
Apply Power Rule: Next, we apply the power of a power rule, which states that a^m)^n = a^{m*n}\. Therefore, \$\frac{1}{2}^4^{\frac{t}{4}} becomes 21^{4*\frac{t}{4}}.
Simplify Exponent: Simplify the exponent by multiplying 4 by (t)/(4), which gives us (1)/(2)t. So, f(t) simplifies to f(t)=1,000×(1)/(2)t.
Compare with Answer Choices: Now, we compare our simplified function to the answer choices.The correct answer choice that matches f(t)=1,000×2t1 is (B) f(t)=1,000×2t1.
More problems from Multiplication with rational exponents